急!急! Logerithmic Functions 9q4

2012-03-31 8:12 am
請詳細步驟教我計下條 :
(不要綱址回答)


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回答 (2)

2012-03-31 9:40 am
參考: F4 science student
2012-04-01 1:44 am
(a)
=log81/2log2-log12/log2-log3/log2
=4log3/2log2-(log4+log3+log3)/log2
=(2log3-log4-2log3)/log2
=-2log2/log2
=-2

(b)
=(2log2/log7)[(1/4*log7)/log2]
=2/4
=1/2

(c)
(log9+3log2)/(log24-log(1/3)
=(log9+log8)/log72
=log72/log72
=1

(d)
=log4/log3-(log6/log3)/(log6/log12)
=log4/log3-(log6/log3)[(log4+log3)/log6]
=(log4-log4-log3)/log3
=-1


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原文連結 [永久失效]:
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