請詳細步驟教我計以下幾條 :
(不要綱址回答)
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急!急! Logerithmic Functions 9q2
2012-03-30 6:35 pm
回答 (2)
2012-03-31 2:41 am
✔ 最佳答案
5c (log8/log5)(log5/log16)log8/log16
3log2/4log2
=3/4
5d [3log(5^2)+2log(2^3)]/6
=log5+log2
=log10
=1
6a (log32/log7)^2
=3.17
6b =0.965
7c =(log100/logx)(3logx)
=6
2012-03-31 12:36 am
5c
=(log8/log5)(log5/log16)
=log8/log16
=3log2/4log2
=0.75
5d
=[3log(5^2)+2log(2^3)]/6
=(6log5+6log2)/6
=log5+log2
=log10
=1
6a
=(log32/log7)^2
=(5log2/log7)^2
=3.17
6b
=√(log2.5/log3-log0.8)
=0.965
7c
=(log100/logx)(3logx)
=2*3
=6
=(log8/log5)(log5/log16)
=log8/log16
=3log2/4log2
=0.75
5d
=[3log(5^2)+2log(2^3)]/6
=(6log5+6log2)/6
=log5+log2
=log10
=1
6a
=(log32/log7)^2
=(5log2/log7)^2
=3.17
6b
=√(log2.5/log3-log0.8)
=0.965
7c
=(log100/logx)(3logx)
=2*3
=6
收錄日期: 2021-04-13 18:38:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120330000051KK00182