F.4 maths --simplify
回答 (3)
2012-03-08 7:34 am
✔ 最佳答案
Let f(x)=x^3- 2x^2 - 2x - 3f(3)=3^3-2(3)^2-2(3)-3=0
∴(x-3)is a factor of f(x).
Use long division
f(x)=(x-3)(x^2+x+1)
∴ x^3- 2x^2 - 2x - 3
=(x-3)(x^2+x+1)
參考: Myself
2012-03-09 4:50 am
x^3 - 2x^2 - 2x - 3
=(x-3)(x^2+x+1)
=(x-3)(x^2+x+1)
2012-03-08 6:49 am
Let f(x) = x^3 - 2x^2 - 2x - 3
f(3) = 27 - 18 - 6 - 3 = 0
(x - 3) is a factor
So, f(x) = (x - 3)(x^2 + x + 1)
f(3) = 27 - 18 - 6 - 3 = 0
(x - 3) is a factor
So, f(x) = (x - 3)(x^2 + x + 1)
收錄日期: 2021-04-20 12:28:15
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