trigonometry prove

2012-03-04 2:21 am
prove
secAsec2Asec4Asec8A=16sinA/sin16A


thanks

回答 (1)

2012-03-04 2:31 am
✔ 最佳答案
Using 2 sinA cosA = sin2A : cosA cos2A cos4A cos8A= sinA cosA cos2A cos4A cos8A / sinA= (1/2)sin2A cos2A cos4A cos8A / sinA= (1/4) sin4A cos4A cos8A / sinA= (1/8) sin8A cos8A / sinA= (1/16) sin16A / sinA= sin16A / (16sinA)SosecA sec2A sec4A sec8A = 16sinA / sin16A


收錄日期: 2021-04-21 22:23:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120303000051KK00558

檢視 Wayback Machine 備份