數學:部分變
回答 (2)
2012-02-29 3:58 am
✔ 最佳答案
p(x)=k1+k2√x k1和k2為非零常數-1=k1+k2 i
-4=k1+2k2 ii
ii-i
-3=k2
代k2=-3入i
-1=k1-3
k1=2
p(x)=2-3√x
p(9)=2-3*3
p(9)=-7
2012-02-28 4:46 am
p(x) = K + A√x
p(1) = K + A = -1
p(4) = K + 2A = -4
A = -3, K = 2
因此p(x) = 2 - 3√ x
代x = 9, p(9) = 2 - 3 * 3 = -7
p(1) = K + A = -1
p(4) = K + 2A = -4
A = -3, K = 2
因此p(x) = 2 - 3√ x
代x = 9, p(9) = 2 - 3 * 3 = -7
收錄日期: 2021-04-26 19:18:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120227000051KK00630