Please solve
8 x^3 - 14x - 6
Maths Factorization
2012-02-23 5:48 am
回答 (2)
2012-02-23 5:58 am
✔ 最佳答案
8x^3 - 14x - 6= 2(4x^3 - 7x - 3)
= 2(4x^3 - 4x - 3x - 3)
= 2[4x(x^2 -1) - 3(x+1)]
= 2[4x(x+1)(x-1) - 3(x+1)]
= 2(x+1)[4x(x-1) -3]
= 2(x+1)(4x^2 - 4x - 3)
= 2(x+1)(2x-3)(2x+1)
參考: Hope the solution can help you^^”
2012-02-23 5:55 am
let 8x^3-14x-6 be f(x)
f(-1)=0
x+1 is factor of f(x)
by using long division
8x^3-14x-6
=(8x^2+8x-6)(x+1)
=2(4x^2+4x-3)(x+1)
=2(2x-1)(2x+3)(x+1)
f(-1)=0
x+1 is factor of f(x)
by using long division
8x^3-14x-6
=(8x^2+8x-6)(x+1)
=2(4x^2+4x-3)(x+1)
=2(2x-1)(2x+3)(x+1)
參考: me
收錄日期: 2021-04-29 00:13:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120222000051KK00929