想請教各位數學
solve the quation 4^x+1=8
回答 (1)
✔ 最佳答案
情況一:4^(x + 1) = 8
4^(x + 1) = 8
(2^2)^(x + 1) = 2^3
2^(2x + 2) = 2^3
2x + 2 = 3
2x = 1
x = 1/2
=====
情況二:(4^x) + 1 = 8
(4^x) + 1 = 8
4^x = 7
log(4^x) = log7
x log4 = log7
x = log7/log4
x ≈ 1.4037
參考: andrew
收錄日期: 2021-04-13 18:32:42
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