Anybody knows how to do it, I need urgently ....thanks^^
Base Area of trapezium in swimming pool :
1/2 {b1 (1)+b2(3) x h (50)}= 100 cm^2
Volume of water in swimming pool : 100 cm^2 x H(20 cm) = 2000 cm^3
if 500 cm^3 water is pumped out, find the depth of water along AB
remarks this is a trapezoid prisms swimming pool, b2=AB=3 cm
Maths problem
2012-02-21 7:00 pm
回答 (1)
2012-02-21 9:24 pm
✔ 最佳答案
Let x cm be the depth of water along AB , then new b1 = 1 - (3 - x) = x - 2new b2 = x{(1/2) [ (x - 2) + x ] * 50} * 20 = 2000 - 500(x - 1) * 1000 = 1500x = 2.5The depth of water along AB = 2.5 cm
收錄日期: 2021-04-21 22:28:48
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