Chemistry - Ans.fyi 參考答案

Chemistry

Shing Hin

2012-02-19 12:49 am

Reaction Stoichiometry and Mass Ratios (two parts)
What mass of the second-listed reactant in each of the following reactions is needed to react completely with 6.913 g of the first-listed reactant?H2O2 + H2S → 2H2O + S

CH4 + 4Cl2 → 4HCl + CCl4

回答 (1)

sioieng

2012-02-19 7:39 am

✔ 最佳答案

1.
Method 1 :
H2O2 + H2S → 2H2O + S
No. of H2O2 = 6.913/(1x2 + 16x2) = 0.2033 mol
No. of moles of H2S = 0.2033 mol
Mass of H2S = 0.2033 x (1x2 + 32.1) = 6.933 g

Method 2 :
H2O2 + H2S → 2H2O + S
(1x2 + 16x2) = 34 g of H2O2 reacts with (1x2 + 32.1) =34.1 g of H2S
Mass of H2S = 6.913 x (34.1/34) = 6.933 g

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2.
Method 1 :
CH4 + 4Cl2 →4HCl + CCl4
No. of moles of CH4 = 6.913/(12 + 1x4) = 0.4321 mol
No. of moles of Cl2 = 0.4321 x 4 = 1.728 mol
Mass of Cl2 = 1.728 x (35.5x2) = 122.7 g

Method 2 :
CH4 + 4Cl2 →4HCl + CCl4
(12 + 1x4) = 16 g of CH4 reacts with (4 x 35.5 x 2) = 284 g of Cl2
Mass of Cl2 = 6.913 x (284/16) = 122.7 g

參考: sioieng

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