Definite integral

Chi Wui

2012-02-19 7:53 am

Evaluate ∫ (-3~10) [(6x^2-16x+1)/(x^2+x+2)]

更新1:

∫ (-3~10) [(6x^2-16x+1)/(x^2+x+2)] dx

回答 (1)

pingshek

2012-02-19 9:23 am

✔ 最佳答案

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參考: miraco

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