Ammonia and carbon dioxide react to form water and a solid urea, (CON₂H₄). In the reaction, 48dm³ of carbon dioxide at r.t.p are converted to urea.
The equation for this reaction is 2(NH₄)+ CO₂-----> 2(H₂O) + (CON₂H₄)
Q1 .Calculate the volume of ammonia at r.t.p which reacted.
Q2. Calculate the mass of urea formed.
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Chemistry - Mole Concept. Help please..?
2012-02-18 7:21 am
回答 (1)
2012-02-18 7:42 am
✔ 最佳答案
Start by writing out the balanced equation properly:2NH3(g) + CO2(g) → 2H2O(g) + CON2H4(s)
At RTP 1 mol gas has volume = 24.0dm³
48dm³ = 2 mol CO2
From the equation: 2 mol NH3 react with 1 mol CO2
Therefore 4 mol NH3 react with 2 mol CO2
At RTP , 4 mol NH3 has volume = 4*24 = 96 dm³
From the equation:
1 mol CO2 will produce 1 mol CON2H4
2mol CO2 will produce 2 mol CON2H4
Molar mass CON2H4 = 60g/mol
2mol = 120g CON2H4 produced.
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