急!急! F4 Polynomials 2.

2012-02-17 2:44 am
請詳細步驟教我計以下三條 :
(不要網址回答)


圖片參考:http://imgcld.yimg.com/8/n/HA05788109/o/701202160072813873437790.jpg

回答 (1)

2012-02-17 4:38 am
✔ 最佳答案
27 f(x) = (x - 5)(x + 2)Q(x) + Ax + BSub. x = 5, f(5) = 9Sub. x = -2, f(-2) = -55A + B = 9-2A + B = -5A = 2, B = -1So, the remainder is 2x - 128(a) f(x) = Q(x)(x + 1)(x - 3) + 2x - 4f(-1) = -6, f(3) = 2(b) f(-1) = m + n - 10 = -6f(3) = 9m - 3n + 74 = 2(c) m + n = 43m - n = -24So, m = -5, n = 929(a) Sub x = -1, we have the remainder is 4(b) 6^2008 + 3 = (-1)^2008 + 3 (mod 7 = 4 (mod 7)So, the day is Thurseday.


收錄日期: 2021-04-13 18:32:31
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120216000051KK00728

檢視 Wayback Machine 備份