✔ 最佳答案
29.
(a)
Dividend = Division * Quotient + Remainder
(x³ + 7x² + 10x + a) ÷ (x + 4) = x² + 3x - 2 ...... remainder = b
Hence, x³ + 7x² + 10x + a = (x + 4)(x² + 3x - 2) + b
Compare the constant terms on the both sides:
a = -8 + b
b = a + 8
(b)
In x³ + 7x² + 10x + a, when a = -8 :
b = (-8) + 8
b = 0
When x³ + 7x² + 10x - 8 is divided by x + 4, the remainder b = 0.
Hence, x³ + 7x² + 10x - 8 is divisible by x + 4.
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30.
(a)
Dividend = Division * Quotient + Remainder
(8x² + px + 5) ÷ (4x + q) = 2x + 1 ...... remainder = 2
Hence, 8x² + px + 5 = (4x + q)(2x + 1) + 2
Compare the constant terms on the both sides :
5 = q + 2
q = 3
Compare the x terms on the both sides :
px = 4x*1 + q*2x
px = 4x + 2qx
p = 4 + 2q
p = 4 + 2*3
p = 10
Hence, p = 10 and q = 3