maths challenging questions

2012-02-15 2:07 am
√(2+√(2+√(2+√(2+√(2+√(2+√(2+√(2+√(2+√(2+√(2+....
=?

回答 (4)

2012-02-15 3:48 am
✔ 最佳答案

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2012-02-15 5:27 am
but it is so complicated and i cannot understand well
2012-02-15 5:22 am
hung is very professional.
Simon YAU, MSc Math
2012-02-15 3:26 am
1)Put √(2+√(2+√(2+...)))=x________________√(2+x)=x___________________2+x=x²________________x²-x-2=0__________x²-x+1/4-9/4=0_ _ __(x-1/2)²-(3/2)²=0(x-1/2+3/2)(x-1/2-3/2)=0_ _ __ _ _ (x+1)(x-2)=0___________________x+1=0 or x-2=0_____________________x= -1 (neg., rej.) or 2_____________________x=2 2)Put_ 1/(1+1/(1+1/(1+...)))=x___________________1/(1+x)=x_________________________1=x+x²____________________x²+x-1=0______________x²+x+1/4-5/4=0_ _ ___ _(x+1/2)²-(√5/2)²=0_ [x+(1+√5)/2][x+(1-√5)/2]=0x+(1+√5)/2=0 or x+(1-√5)/2=0x= -(1+√5)/2 (neg., rej.) or (√5-1)/2x=(√5-1)/2
參考: I Hope This Can Help You ! ^_^ ( From Me )


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