這兩題函數怎樣做?

1)h(u) = 9 -4u = 13∴-4u = 4u = -1 2)a H(x) = k/√(x -2) H(3) + H(6) = 18 k/√(3 -2) + k/√(6 -2) = 18

2012-02-13 18:01:16 補充：
k/1 + k/2 = 18

3k/2 = 18

k =12


b)

若 H(u) = 4

∴ 12/√(u -2) = 4

3/√(u -2) = 1

√(u -2) = 3

(u -2) = 9

u =11