這兩題函數怎樣做?
2012-02-14 12:17 am
回答 (1)
2012-02-14 2:00 am
✔ 最佳答案
1)h(u) = 9 -4u = 13∴-4u = 4u = -1 2)a H(x) = k/√(x -2) H(3) + H(6) = 18 k/√(3 -2) + k/√(6 -2) = 18 2012-02-13 18:01:16 補充：
k/1 + k/2 = 18
3k/2 = 18
k =12
b)
若 H(u) = 4
∴ 12/√(u -2) = 4
3/√(u -2) = 1
√(u -2) = 3
(u -2) = 9
u =11
收錄日期: 2021-04-13 18:31:58
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120213000051KK00452