數學 對數問題

2012-02-12 1:41 am
1)
㏒2 √8-㏒4 32

2)(㏒x√x+㏒x 3√x)-(㏒y√y^5-㏒y√y)

回答 (2)

2012-02-12 5:40 am
參考: I Hope This Can Help You ! ^_^ ( From Me )
2012-02-12 6:34 am
Another way to do it:
x = ㏒2 √8, y = ㏒4 32
2^x = (2^3)^(1/2), 2^x = 2^(3/2), x = 1.5
(2^2)^y = 2^5, 2y = 5, y = 2.5
x – y = 1.5 – 2.5 = -1


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