A question about probabiltiy

2012-02-04 11:44 pm
Hi, I am studying for a quiz. Please help me with the following question. I did not get the answer. Ninety eight percent of all babies survive delivery. However,15 percent of all births involve Cesarean C sections, and when a C section isperformed, the baby survives 96 percent of the time. If a randomly chosenpregnant woman does not have a C section, what is the probability that her babysurvives? Ans: 0.9835

回答 (1)

2012-02-05 3:26 am
✔ 最佳答案
(1 - 15%) P(E) + (15%) (96%) = 98%P(E) = 0.9835...


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