If the region bounded by the parabola y=4-(x+5)^2 and the x-axis is revolved about the y-axis, find the volume of the solid of revolution.
In this case, as the solid is revolved about the y-axis, should
V=Int pi (x1^2-x2^2) [d,c] be used? but there is no x2?
更新1:
sorry should beV=Int pi (x1^2-x2^2)dy [d,c]