根式/通分母 問題

2012-01-28 12:50 am
1.

x = 100 - 5000/100-y
點樣轉為
x= 100(50-y) / 100-y

2.如果通分 : 個100應該只乘-y 定乘全個分母100-y

x = 100 - 5000/100-y

x = [100 (-y)-5000] / 100-y

3. 根式有理化 ? :

1 / 根3-2

係1 / 根3-2
乘根3+2?


回答 (1)

2012-01-28 1:20 am
✔ 最佳答案
1.
x = 100 - 5000/(100-y)
x = [100(100-y) - 5000]/(100-y)
x = [10000-100y-5000]/(100-y)
x = [5000-100y]/(100-y)
x = 100(50-y)/(100-y)

2.
as above, (100-y) should be read as 1 whole item in this step
just like if the fraction is w/(5-2), you won't mutiply it by 5 or 2

3.
use (a+b)(a-b) = a^2 - b^2
1/[sqrt(3)-2]
= [sqrt(3)+2] / {[sqrt(3)-2][sqrt(3)+2]}
= [sqrt(3)+2] / {[sqrt(3)]^2 - 2^2]}
= [sqrt(3)+2] / {3 - 4}
= -[sqrt(3)+2]


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