F.5 Maths Questions.

2012-01-25 12:53 am

回答 (1)

2012-01-25 1:10 am
✔ 最佳答案
1 a = 2 * 1 + 3 = 5T(n + 1) - T(n) = 2=> difference = 2Let (n/2)[10 + 2(n - 1)] < 30002n^2 + 9n - 6000 < 0 -57.0605 < n < 52.5605So, the greatest value of m is 52 (A)2 a = logb/log121/a = log12/logb = log_b 12 (B)3 We have x = kt^alog_3 x = log_3 k + alog_3 tSub. log_3 t = 0 => log_3 k = -4k = 3^(-4) = 81 (B)

2012-01-24 17:11:55 補充:
The last line should be 3^(-4) = 1/81 (A)


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