Trigonometry

2012-01-23 10:36 pm

回答 (1)

2012-01-23 10:53 pm
✔ 最佳答案
Key theorem: sin2A = 2sinAcosA

sin(π/5)cos(π/5)cos(2π/5)cos(4π/5)cos(18π/5)

= sin(π/5)cos(π/5)cos(2π/5)cos(4π/5)cos(8π/5)

= (1/2)(2)sin(π/5)cos(π/5)cos(2π/5)cos(4π/5)cos(8π/5)

= (1/2)sin(2π/5)cos(2π/5)cos(4π/5)cos(8π/5)

= (1/4)sin(4π/5)cos(4π/5)cos(8π/5)

= (1/8)sin(8π/5)cos(8π/5)

= (1/16)sin(16π/5)

= -(1/16)sin(π/5)

So, cos(π/5)cos(2π/5)cos(4π/5)cos(18π/5) = -1/16



收錄日期: 2021-04-26 19:18:13
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120123000051KK00199

檢視 Wayback Machine 備份