指數函數一條

2012-01-09 1:14 am
(-a^0 b^-2/3)^3

回答 (2)

2012-01-09 6:05 am
(-a^0 b^-2/3)^3
=(-b^-2/3)^3
=-b^-6/3
=-b^-2
=-1/b^2
2012-01-09 1:23 am
x^0=1 (x=/=0)
SO(-a)^0=1
原式=(b^-2/3)^3
=b^(-2/3*3)
=b^-2
參考: BRIAN


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