4 mc question

2012-01-06 1:21 am
16) For a chemical cell, there are two half-cellsHalf-cell A contains zinc metal and zinc nitratesolutionHalf-cell B contains silver and silver nitratesolutionThe two half-cells are linked by an externalcircuit and a salt bridgeWhich of the following is INCORRECT?A. Zinc is anodeB. Reduction occurs at the silver electrodeC. The salt bridge can be made by soaking a pieceof filter paper with dilute sodium chloride solutionD. Anions in the salt bridge move towards the zincnitrate solution. 17) For a chemical cell, there are two half-cellsHalf-cell A contains nickel metal and nickel(II)sulphate solutionHalf-cell B contains cadmium and cadmium sulphatesolutionThe two half-cells are linked by an externalcircuit and a salt bridgeWhich of the following is correct?A. Oxidation occurs at the nickel electrodeB. Cadmium electrode is the cathodeC. The concentration of cadmium ion in cadmiumsulphate solution increasesD. Nickel(II) sulphate solution can be stored in acadmium can 18) Which of the following statements concerningMnO2 in zinc-carbon cell is correct? (i) Itacts as an oxidizing agent (ii)The oxidation number of MnO2 changes from +4 to +2 over disvharge (iii)MnO2 is used to remove the hydrogen produced in the cellA. i and iiB. i and iiiC. ii and iiiD.i, ii and iii 19) For a chemical cell, there are two half-cellsHalf-cell A contains carbon and sodium bromidesolutionHalf-cell B contains carbon and acidified potassiumdichromate solutionThe two half-cells are linked by an externalcircuit and a salt bridgeWhich of the following is correct?A. Species being oxidized: Cr2O7 2- ; species beingreduced: Br-B. Species being oxidized: Br- ; species beingreduced: Cr2O7 2-C. Species being oxidized: K+ ; species beingreduced: Na+D. Species being oxidized: Na+ ; species beingreduced: K+
更新1:

其實我係想對答案, 我的答案: C,C,B,D

回答 (2)

2012-01-06 6:20 am
✔ 最佳答案
16. A is correct. Zn is oxidized to give Zn^2+.
B is correct. Ag^+ is reduced to give Ag coated on the cathode.
C is incorrect. Cl^- in NaCl may react with Ag^+ to form insoluble AgCl, which lowers the electrical conductivity of the cell.
D is correct. Anions carrying -ve charge move towards to ZnNO3 solution to balance the excess amount of +ve charge of Zn^2+ produced.

17. For option A and B, if you don't know which one is correct, just compare these two options. Suppose A is correct, nickel is oxidized so nickel is anode. Then cadmium is cathode, where reduction occurs, then B is also correct. But there could not be two correct answers in MCQ. So they contradict.
A and B are incorrect. Of course in fact, cadmium is more reactive than nickel, so cadmium loses electrons more readily to give oxidation, while nickel ions should be reduced.
C is correct. As mentioned before, cadmium is oxidized to give cadmium ions, so cadmium ions concentration should increase.
D is incorrect. Displacement reaction occurs as cadmium is more reactive than nickel.

18. (1) is correct.
2MnO2 + H2 ---> Mn2O3 + H2O
MnO2 is reduced by H2 formed from zinc-carbon cell. In this case, MnO2 is an oxidizing agent.
(2) is incorrect, the O.N. of Mn decreases from +4 to +3 in the reaction.
(3) is correct, please refer to (1).
Ans: B

19. In half cell A, solution contains Na^+, Br^-.
In half cell B, solution contains K^+, Cr2O7^2-.
Obviously, Cr2O7^2- acts as oxidizing agent in B and Br^- acts as reducing agent. Na^+, K^+ are neither oxidizing agent nor reducing agent because they are too unreactive.
So Cr2O7^2- is reduced, Br^- is oxidized.
Ans: B
參考: Knowledge is power.
2012-01-06 1:53 pm
如果對方問問題之餘有講解自己不明白的地方, 或者是說說自己對解題的意見, 那還值得幫; 如此直接就九版問題, 明顯是想抄功課算數的懶鬼, 別管了.


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