Percent yield of a reaction?

[匿名]

2011-12-23 4:46 pm

C2H4 (g) +H2 (g) ->C2H6 (g)

C2H4 flows into a catalytic reactor at 25 atm and 300 degree C with a flow rate of 1228L/min. Hydrogen at 25 atm and 300 degree C flows into the reactor at a flow rate of 1500 L/min. If 11 kg of C2H6 are collected per minute, what is the percent yield of the reaction?

Question: ? %

回答 (1)

Trevor H

2011-12-23 6:15 pm

✔ 最佳答案

From the balanced equation:
1 litre of C2H4 reacts with 1 litre H2 to produce 1 litre C2H6
You have 1286L/min of C2H4 and 1500L/min of H2 - C2H4 is limiting. The reaction will produce 1286L/min of C2H6
To determine the mass of C2H6 produced use the gas law equation to calculate mol of C2H6

PV = nRT
25*1286 = n*0.082057*573
n = 32,150 / 47.02
n = 683.77 mol theoretical production

Molar mass C2H6 = 24+6 = 30g/mol
683.77 mol = 683.77 * 30 = 20,513g or 20.513kg

Actual production was 11.0kg

% yield = 11/20.513*100 = 53.6% yield.

👍 0 👎 0