數學-代數方程

2011-12-23 4:31 am
啲代數方程好難..
有冇人可以幫我解答下...><

1) 3分之2-x減2分之1=3分之4

2)13-3分2=x

3) 3分之y-3=9

4)6分之7-x=-4

回答 (3)

2011-12-23 10:18 pm
✔ 最佳答案
1.
[(2 - x)/3] - (1/2) = 4/3
[(2 - x)/3] - 4/3 = 1/2
(2 - x- 4) / 3 = 1/2
(2 - x- 4) = 3/2
-2 – x = 3/2
-2 = 3/2 + x
x = -2 – 3/2
x = -4/2 – 3/2x = -7/2

2.
13 - (2/3) = x
(39/3) - (2/3) = x
x = 37/3

3.
(y - 3)/3 = 9
y - 3 = 27
y = 27 + 3
y = 30

4.
(7 - x)/6 = -4
7 - x = -24
7 = -24 + x
x = 7 + 24
x = 31
參考: Me
2012-01-20 4:38 am
[(2 - x)/3] - (1/2) = 4/3
[(2 - x)/3] - 4/3 = 1/2
(2 - x- 4) / 3 = 1/2
(2 - x- 4) = 3/2
-2 – x = 3/2
-2 = 3/2 + x
x = -2 – 3/2
x = -4/2 – 3/2x = -7/2
啲代數方程好難..
有冇人可以幫我解答下...><
2011-12-23 7:29 am
1.
{(2-x)/3} - (1/2) = 3/4
4(2-x) - 6 = 9
8 - 4x = 15
-4x = 7
x = -7/4

2.
13 - (2/3) = x
(39/3) - (2/3) = x
(39-2)/3 = x
x = 37/3

3.
(y-3)/3 = 9
(y-3) = 27
y = 30

4.
(7-x)/6 = -4
(7-x) = -24
-x = -31
x = 31


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