Limit + integral

2011-12-23 3:57 am
Evaluate:

lim(n->∞) [1/√(9n² - 1²) + 1/√(9n² - 2²) + 1/√(9n² - 3²) + ... + 1/√(9n² - n²)]

回答 (1)

2011-12-23 4:09 am
✔ 最佳答案

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