更新1:
To : Lost Gor. Space means perpendicular distance between the lines is 4 units.
Equation of straight lines
2011-12-22 3:59 pm
Find equation(s) of straight lines that are parallel to 4x - 3y = 8 and with a space of 4 units.
回答 (2)
2011-12-22 8:11 pm
✔ 最佳答案
As the slope should be the same, let the required equation is4x - 3y + c = 0
Then choose one point from 4x - 3y = 8. e.g (5,4)
Then |4(5) - 3(4) + c|/5 = 4
|c + 8| = 20
c = 12 or c = -28
So, the required equation are
4x - 3y + 12 = 0 or 4x - 3y - 28 = 0
2011-12-22 7:32 pm
sor 我英文唔好 比我用中文答;
firstly 你將4x - 3y = 8 變做y=mx+c先
即y=4x/3-8/3
如果距離4單位 而斜率一樣 即係y=mx+c 既m一樣 c+-4
所以equation(s) of straight :
y=4x/3-8/3+4 同y=4x/3-8/3-4
=> y=4x/3-4/3同 y=4x/3-20/3
以上答案未必準確，若有錯漏，還望指正
firstly 你將4x - 3y = 8 變做y=mx+c先
即y=4x/3-8/3
如果距離4單位 而斜率一樣 即係y=mx+c 既m一樣 c+-4
所以equation(s) of straight :
y=4x/3-8/3+4 同y=4x/3-8/3-4
=> y=4x/3-4/3同 y=4x/3-20/3
以上答案未必準確，若有錯漏，還望指正
參考: lostgor
收錄日期: 2021-04-26 19:16:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111222000051KK00143