1) a^2-b^2+2b-1=
ans: (a-b+1)(a+b-1)
2. Let Tn be the nth term of the sequence. If T1=4, T2=5 and T(n+2)=
Tn+T(n+1) for any positive integer n, then T10=
ans:254
3. 10100100001001(2)=
ans: 2^13+2^11+137
pls show clear steps.thanks
maths sample paper questions
2011-12-14 4:51 am
回答 (1)
2011-12-14 5:07 am
✔ 最佳答案
1 a^2 - b^2 + 2b - 1= a^2 - (b^2 - 2b + 1)= a^2 - (b - 1)^2= (a + b - 1)(a - b + 1)2 T(3) = 4 + 5 = 9T(4) = 5 + 9 = 14T(5) = 23T(6) = 14 + 23 = 37T(7) = 60, T(8) = 97, T(9) = 157, T(10) = 2543 10100100001001(2)= 2^13 + 2^11 + 2^8 + 2^3 + 2^0= 2^13 + 2^11 + 137
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