a maths question please?

2011-12-11 7:35 am
hey guys, i'm not too good at writing maths functions on computer so i hope u can understand what i mean!
can you help me simplify this in detail please?
(m/n - n/m) / (1/m square - 1/n square)
final answer is -mn thanks !

回答 (3)

2011-12-11 7:40 am
✔ 最佳答案
(m/n - n/m)/(1/m² - 1/n²)
Multiply num. and den. by m²n²
= (m³n-n³m)/(n²-m²)
= mn(m²-n²)/(n²-m²)
= -mn(n²-m²)/(n²-m²)
= -mn
2011-12-11 3:42 pm
(m/n – n/m) ÷ (1/m² – 1/n²)
(m² – n²/mn) ÷ [(n² – m²)/m²n²]
(m² – n²/mn) ÷ [–(m² – n²)/m²n²]
(m² – n²/mn) × m²n²/[–(m² – n²)]
(1/mn) × m²n²[–(1)]
(mn) × [–(1)]
= – mn
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2011-12-11 3:42 pm
=(m^2-n^2)/mn /(n^2-m^2)/ m^2n^2=
=-mn
God bless you.


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