✔ 最佳答案
general equation: logab = c => a^c = b
such that you can derive by yourself: logab = log a / log b whatever the base is
22a.
log5 0.6 = log10 0.6 / log10 5
= log10 (3/5) / b
= (log10 3 - log10 5) / b
= (a-b)/b
22c.
log10 (2/27) = log10 (2) - log10 (27)
= log10 (10/5) - log10 (3^3)
= log10 (10) - log10 (5) - 3log10 (3)
= 1 - b - 3a
23a.
log x = 2 log y
log x = log (y^2)
x = y^2
23b.
log (xy) = 2
log (xy) = log 100
xy = 100 => x = 100/y
23c.
(1/2)log x = 2 + log y
log [x^(1/2)] = log 100 + log y
log [x^(1/2)] = log (100y)
x^(1/2) = 100y
x = 10000y^2
24d.
log4 (x-2y) = 3
log4 (x-2y) = 3 log4 (4)
log4 (x-2y) = log4 (4^3)
x-2y = 64
x = 64 + 2y