(a) p=2.72^(-h/8.55)
h=5072 (m)=5.072 (km)
p=2.72^(-5.072/8.55)
p=0.55234
At sea level, p=1
p/1=0.55234=55.234%
The atmospheric pressure at the Tanggula Pass is 55.2% of that at sea level.
(b) p=2.72^(-h/8.55)
h=8.848
p=2.72^(-8.848/8.55)
p=0.35505
At sea level, p=1
p/1=0.35505=35.505%
The atmospheric pressure at the Qomolangma Feng is 35.5% of that at sea level.