1.lim x ->infinity ((x-7)/(x-5))^x
ans: e^-2
2.lim x ->-1 {sin(x+1)}/(x^2-1)
ans: -1/2
3.lim x ->infinity xln(1+5/x+6/x^2)
ans: 5
4. lim x ->infinity {[(x+4)(1+2/x-15/x^2)]/x}^x
ans: e^6
plz show steps
收錄日期: 2021-04-13 18:24:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111207000051KK00665