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圖片參考：http://imgcld.yimg.com/8/n/HA00997022/o/701112060044213873407930.jpg
急 ! F4 數 Function 5
2011-12-06 10:44 pm
回答 (2)
2011-12-06 10:54 pm
✔ 最佳答案
a.f(-x) = (-x)^3 - 3(-x)
f(-x) = -x^3 + 3x
f(-x) = -(x^3 - 3x)
f(-x) = -f(x)
b.
f(-x) = -f(x) from a
f(-x) + f(x) = 0
so f(99) + f(-99) = 0
2011-12-06 10:59 pm
f(x) = x^3 - 3x
(a) f(-x) = (-x)^3 - 3(-x) = -(x^3 - 3x) = -f(x)
since , f(x) is an odd function
f(99) + f(-99) = f(99) - f(99) = 0
圖片參考：http://latex.codecogs.com/gif.latex?f(x)=x^3-3x\\ (a)$ $ f(-x)=(-x)^3-3(-x)=-(x^3-3x)=-f(x)\\ $since , $f(x) $ is an odd function$\\ (b)$ $ f(99)+f(-99)=f(99)-f(99)=0
(a) f(-x) = (-x)^3 - 3(-x) = -(x^3 - 3x) = -f(x)
since , f(x) is an odd function
f(99) + f(-99) = f(99) - f(99) = 0
圖片參考：http://latex.codecogs.com/gif.latex?f(x)=x^3-3x\\ (a)$ $ f(-x)=(-x)^3-3(-x)=-(x^3-3x)=-f(x)\\ $since , $f(x) $ is an odd function$\\ (b)$ $ f(99)+f(-99)=f(99)-f(99)=0
收錄日期: 2021-04-13 18:23:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111206000051KK00442