Change the subject of the formulae to the letter in the square brackets
1/(x-2y) + 1/z = z [x]
Correct Ans is :
x = z/(z^2-1) + 2y
PLZ Give Me the STEPS
F.2 MATH Questions~Help~Fast~
2011-12-03 5:32 am
回答 (2)
2011-12-03 6:40 am
1/(x-2y)+1/z=z [x]1/(x-2y)=z-1/z1/(x-2y)=(z²-1)/zx-2y=z/(z²-1)x=z/(z²-1)+2y
參考: Hope I Can Help You ! ^_^ ( From Me )
2011-12-03 5:43 am
收錄日期: 2021-04-13 18:22:56
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