x x
_ + _ < 1
4 2
Solve 2x(2次)-9x-18=0
Maths questions(1)
2011-12-02 9:09 am
回答 (1)
2011-12-02 9:53 am
✔ 最佳答案
as follows~~1)
x/4 + x/2 < 1
x + 2x < 4
3x < 4
x < 4/3
2)
2x^2 - 9x -18 = 0
(2x+3)(x-6) = 0
x = -3/2 OR x = 6
收錄日期: 2021-04-15 18:44:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111202000051KK00042