✔ 最佳答案
設h(x,y)=(x^2/y)+(y^2/x),x,y皆複數,求h((1-√2i)/(1+i),(1+√2i)/(1+i ))=___
Sol
x=(1-√2i)/(1+i),y=(1+√2i)/(1+i)
x+y=2/(1+i)=2(1-i)/2=1-i
xy=(1+2)/(1+2i-1)=3/(2i)=-3i/2
(x+y)/(xy)=(1-i)/(-3i/2)=(2-2i)/(-3i)=(2+2i)/3
(x^2/y)+(y^2/x)
=x^3/(xy)+y^3/(xy)
=(x^3+y^3)/(xy)
=[(x+y)^3-3(x+y)xy]/(xy)
=(x+y)^2*(x+y)/(xy)-3(x+y)
=(1-i)^2*(2+2i)/3-3(1-i)
=(-2i)(2+2i)/3-3+3i
=(4-4i)/3-3+3i
=-5/3+5i/3