Find the max. and min. value of (8xy+12yz-8y²+z²+u²)/(x²-2xy+5y²+z²+9u²)
where x,y,z,u are any real numbers and (x,y,z,u)≠(0,0,0,0).
求(8xy+12yz-8y²+z²+u²)/(x²-2xy+5y²+z²+9u²)的最大小值,其中(x,y,z,u)≠(0,0,0,0)
收錄日期: 2021-04-24 10:08:16
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https://hk.answers.yahoo.com/question/index?qid=20111128000051KK01033