Calculus (Tangents to curves)
2011-11-24 3:22 am
The equation of the tangent to a curve y=u(x) at x=a is y=(-2a+4)(x-a)+k, where k is a constant. Given that the curve touches the x-axis at x=2, find the value of k.
回答 (1)
2011-11-24 8:24 am
✔ 最佳答案
As the equation of tangent to the curve at x = a is given by y = (-2a + 4)(x - a) + kAs the curve touches the x-axis at x = 2,
So, at x = 2, equation of tangent: y = (-2(2) + 4)(x - 2) + k = 0
So, k = 0
參考: Prof. Physics
收錄日期: 2021-04-20 11:51:24
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