0.985g of an anhydrous metal carbonate (formula XCO3)required 40.0cm^3 of 0.250 M hydrochloric acid for complete neutralization.
Calculate the reative atomic mass of the metal X.
chem[10分]
2011-11-22 6:27 am
回答 (2)
2011-11-22 7:47 am
✔ 最佳答案
XCO3 + 2HCl → XCl2 + H2O+ CO2No. of moles of HCl = 0.25 x (40/1000) = 0.01 mol
No. of moles of XCO3 = 0.01 x (1/2) = 0.005 mol
Molar mass of XCO3 = 0.985/0.005 = 197 g/mol
Relative atomic mass of X = 197 - (12 + 16x3) = 137
參考: Tsui
2011-11-22 7:58 am
The Calculation As Follow:
圖片參考：http://imgcld.yimg.com/8/n/HA05709917/o/701111210101913873403870.jpg
圖片參考：http://imgcld.yimg.com/8/n/HA05709917/o/701111210101913873403870.jpg
收錄日期: 2021-04-13 18:22:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111121000051KK01019