Give 9.60g of ammonium carbonate (NH4)2CO3,find
a)the number of moles of the compound.
b)the number of moles of ammonium ions.
c)the number of moles of carbonate ions.
d)the number of moles of hydrogen atoms.
e)the number of hydrogen atoms.
chem計數[10分]
2011-11-22 6:02 am
回答 (1)
2011-11-22 6:22 am
✔ 最佳答案
a)Molar mass of (NH4)2CO3 = 14x2 + 1x8 + 12 +16x3 = 96 g/mol
No. of moles of (NH4)2CO3 = 9.6/96 = 0.1 mol
b)
Each mole of (NH4)2CO3 consists of 2 moles ofNH4^+ ions.
No. of moles of NH4^+ ions = 0.1 x 2 = 0.2 mol
c)
Each mole of (NH4)2CO3 consists of 1 mole ofCO3^2- ions.
No. of moles of CO3^2- ions = 0.1 mol
d)
Each mole of (NH4)2CO3 consists of 4 x 2 = 8moles of H atoms.
No. of moles of H atoms = 0.1 x 8 = 0.8 mol
e)
No. of H atoms = 0.8 x (6.02 x 10^23) = 4.816 x 10^23
參考: Tsui
收錄日期: 2021-04-13 18:22:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111121000051KK00983