✔ 最佳答案
1/3 = 1+3/5+7
??!!
2011-11-20 19:40:38 補充:
哦……………………………
2011-11-20 21:48:18 補充:
Let T₁=1/3,(1+3)/(5+7),(1+3+5)/(7+9+11),… T₁(1)=1/3T₁(2)=(1+3)/(5+7)T₁(3)=(1+3+5)/(7+9+11)…T₁(n)=[1+…+(2n-1)]/{(2n-1+2)+…+[2(2n-1)+1]}T₁(n)=[1+…+(2n-1)]/[(2n+1)+…+(4n-1)]T₁(n)={[1+(2n-1)]n/2}/{[(2n+1)+(4n-1)]n/2}T₁(n)=[1+(2n-1)]/[(2n+1)+(4n-1)]T₁(n)=(2n)/(6n)T₁(n)=1/3
Let T₂=2/4,(2+4)/(6+8),(2+4+6)/(8+10+12) T₂(1)=2/4=T₂(2)=(2+4)/(6+8)T₂(3)=(2+4+6)/(8+10+12)…T₂(n)=(2+…+2n)/[(2n+2)+…+2(2n)]T₂(n)=(1+…n)/[(n+1)+…2n]T₂(n)=[(1+n)n/2]/{[(n+1)+2n]n/2}T₂(n)=(1+n)/[(n+1)+2n]T₂(n)=(1+n)/(1+3n)
2011-11-20 21:58:57 補充:
So,
T₁=1/3
T₂(n)=(1+n)/(1+3n)
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