Solve the following differential equation.
a). ( x - 1 )y' = y + 2(x - 2)^3
b). x^3y' + (2 - 3x^2)y = x^3
c). y' + (2cos x)y = sin^2x cosx
d). x^2y' + 3xy = 4x^2 + 2
Differential equation
2011-11-20 11:06 pm
回答 (1)
2011-11-21 1:56 am
收錄日期: 2021-04-23 23:26:24
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