By putting t = π/2-2x, show that ∫ dx/1+sin(2x) = 1/2 [tan(x-π/4)]+C where C is a constant.
dt = -2 dx
dx = dt/-2
t = π/2-2x
x = (t-π/2)/-2
所以 ∫ dx/1+sin(2x) = -1/2 ∫ dt/1+cos t
跟著我唔識做落去......
integration by substitution
2011-11-15 10:40 pm
回答 (1)
2011-11-16 12:00 am
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