If ∂²f/∂x²+∂²f/∂y²= e^(-x²-y²) for all (x,y) in x²+y² < 1,
evaluate ∫∫_(x²+y²<1) (x ∂f/∂x+y ∂f/∂y) dx dy.
設∂²f/∂x²+∂²f/∂y²= e^(-x²-y²) ,(x,y) in x²+y² < 1,
試求 ∫∫_(x²+y²<1) (x ∂f/∂x+y ∂f/∂y) dx dy 之值.
double integral
2011-11-15 6:45 am
回答 (2)
2011-11-16 5:33 am
2011-11-16 12:31 am
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收錄日期: 2021-04-23 23:27:20
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