F.5 PROBABILITY

2011-11-13 2:26 am
16. in an industry, the probability for a worker to get an occupational disease is 1/4 if five workers in this industry are chosen at random,

what is the probability of three or more of them get the disease?"
更新1:

the answer is 53/512

回答 (2)

2011-11-13 2:48 am
✔ 最佳答案
P(three or more of them get the disease)

= P(three have disease) + P(four have disease) + P(five have disease)

(They are mutually exclusive events)

= 5C3 * (1/5)^3 * (1 - 1/5)^2 + 5C4 * (1/5)^4 * (1 - 1/5) + (1/5)^5

= 181/3125
參考: Prof. Physics
2011-11-15 10:41 pm
change 1/5 to 1/4 and you will get the correct answer


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