Solve the system using elementary row operations?

2011-11-11 1:01 pm
Solve the system using elementary row operations?
Can't seem to figure this out.

1)
x+3y=10
4x-2y= -16

2)
5x-3y= -5
- 3x + 3y =9
更新1:

MATRICES!

回答 (3)

2011-11-11 1:15 pm
✔ 最佳答案
2(x + 3y) + 3(4x - 2y) = 2(10) + 3(- 16)
2x + 6y + 12x - 6y = 20 - 48
14x = - 28
x = - 2

- 2 + 3y = 10
3y = 12
y = 4

Answer: x = 2, y = 4
-----------
5x - 3y - 3x + 3y = - 5 + 9
2x = 4
x = 2

5(2) - 3y = - 5
3y = 10 + 5
3y = 15
y = 5

Answer: x = 2, y = 5
2016-11-29 8:40 pm
(a million)i'm utilising an bigger triangular matrix; 3 -3 5 6 a million 7 5 4 a million 2 3 9/5 divide r3 via 5 a million -a million 5/3 2 divide r1 via 3 a million 7 5 4 a million 2 3 9/5 a million -a million 5/3 2 0.5 2 11/5 r2-r3 a million 2 3 9/5 a million -a million 5/3 2 0.5 2 11/5 0 3 4/3 -a million/5 r3-r1 a million -a million 5/3 2 0.5 2 11/5 0 0 2/15 -38/25 r3-(3/5)r2 a million -a million 5/3 2 0 a million 2/5 11/25 r2/5 0 0 a million -fifty seven/25 r3/15 we've an bigger triangular matrix. x3= -fifty seven/25 artwork returned via substitution for x2=5 and artwork returned in r1 x1=26. (2) (6,4,7) =x1(3,a million,5)+x2(-3,7,10) +x3(5,5,15) =26(3,a million,5)+5(-3,7,10) -(fifty seven/5)(5,5,15) I want you a rapid restoration out of your ailment.
2011-11-11 1:15 pm
x+3y=10 ......(1)
4x-2y= -16 ......(2)
4(1)-(2): 14y=56
y=4
substitute to (1): x+12=10
x=-2

5x-3y=-5 ......(1)
-3x+3y=9 ......(2)
3(1)+5(2): 6y=30
y=5
substitute to (1): 5x-15=-5
x=2


收錄日期: 2021-05-01 00:53:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111111050130AAAwbSo

檢視 Wayback Machine 備份