Solve simultaneous equations by using matrix method?
I don't know how to use the matrix method at all.
(a)
2x+2y = 2
4x+3y=7
(b)
5x-3y=-5
-3x+3y=9
回答 (3)
I don't know. I think the people before me might have needlessly overcomplicated things.
I'd just use Cramer's rule.
The determinant of the (a) system is
| 2 2 |
| 4 3 | = 2*3 - 4*2 = -2 (Thus it does have a solution)
The x-determinant of the system is (just switch the coefficients of x with the right-hand sides'):
| 2 2 |
| 7 3 | = 2*3 - 7*2 = -8
The y-determinant is:
| 2 2 |
| 4 7 | = 2*7 - 4*2 = 6
The solution is thus: det(x)/det(system), det(y)/det(system)
Or, rather: 4, -3
Inverse of a Matrix
Matrix Inverse
Multiplicative Inverse of a Matrix
For a square matrix A, the inverse is written A-1. When A is multiplied by A-1 the result is the identity matrix I. Non-square matrices do not have inverses.
Note: Not all square matrices have inverses. A square matrix which has an inverse is called invertible or nonsingular, and a square matrix without an inverse is called noninvertible or singular.
AA-1 = A-1A = I
Example: For matrix , its inverse is since
AA-1 =
and A-1A = .
Here are three ways to find the inverse of a matrix:
1. Shortcut for 2x2 matrices
For , the inverse can be found using this formula:
Example:
2. Augmented matrix method
Use Gauss-Jordan elimination to transform [ A | I ] into [ I | A-1 ].
Example: The following steps result in .
so we see that .
3. Adjoint method
A-1 = (adjoint of A) or A-1 = (cofactor matrix of A)T
Example: The following steps result in A-1 for .
The cofactor matrix for A is , so the adjoint is . Since det A = 22, we get
.
See also
Determinant of a matrix, cofactor
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