1).(m+5)/2-(m-6)/9=9
2).-(m+17)/8+(m+4)/5=-3
(P+13)/11+(p-2)/7=3
7(P+13)+11(P-2)=231
7P+91+11P-22=231
7P+11p=231-91+22
18P/18=162/18
P=9
右邊的231點得出來?
math方程f.1
2011-11-08 4:07 am
回答 (1)
2011-11-08 7:03 am
✔ 最佳答案
1). (m+5)/2 - (m-6)/9 = 92*9*(m+5)/2 - 2*9*(m-6)/9 = 2*9*9
9m + 45 - 2m + 12 = 162
7m = 162 - 45 - 12
7m = 105
m = 15
2). -(m+17)/8 + (m+4)/5 = -3
- 5*8*(m+17)/8 + 5*8*(m+4)/5 = -3*5*8
-5m - 85 + 8m + 32 = -120
3m = -120 + 85 - 32
3m = -67
m = -22(1/3)
(P+13)/11 + (P-2)/7 = 3
11*7*(P+13)/11 + 11*7*(P-2)/7 = 11*7*3
7(P+13) + 11(P-2) = 231
收錄日期: 2021-04-13 18:21:13
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https://hk.answers.yahoo.com/question/index?qid=20111107000051KK00763