F.2 factorization!!!

2ax+2ay-4bx-4by-2az+4bz
=2a(x+y)-4b(x+y)-2z(a+2b)
=(x+y)(2a-4b)-2z(a+2b)
=2(a-2b)(x+y)-2(a+2b)
=(a-2b)[2(x+y)-2z]
=2(x+y-z)(a-2b)

2ax+2ay-4bx-4by-2az+4bz
= 2ax+2ay-2az - 4bx-4by+4bz
= 2a (x+y-z) -4b (x+y-z)
= (2a-4b)(x+y-z)

2011-11-03 00:24:18 補充：
後面應該仲要
= (2a-4b)(x+y-z)
= 2(a-2b)(x+y-z)

2ax+2ay-4bx-4by-2az+4bz
=2a(x+y)-4y(a+b)-2z(a+b)
=2a(x+y)-(4y+2z)(a+b)

I am not sure the answar

2ax+2ay-4bx-4by-2az+4bz

=2x(a-2b)2y(a-2b)-2z(a-2b)

=(a-2b)(2x+2y-2z-2b)

2011-11-02 20:56:07 補充：
sorry

answer is(a-2b)(2x+2y-2z)


sorry!!!