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phy-electromagnetism
2011-11-01 5:39 am
回答 (1)
2011-11-01 6:02 am
✔ 最佳答案
Induced emf = -NA.(dB/dt)where N is the no. of turns of the coil
A is the cross-sectional area
dB/dt is the rate of flux change
Given dB/dt = 4x10^-3/0.5 T/s = 8x10^-3 T/s
A = pi x 0.1^2 m^2 = 0.0314 m^2
Hence, induced emf = 100 x 0.0314 x 8x10^-3 v = 0.025 v
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111031000051KK00953